2025()*+!,-4./012!#$%&'(1.【34】B【56】789:;<=>?@,AABC;DEFGHIJKLMN,OPKQR#,BAST;FGUVWNX¶éçÁ,êë>ìí,AAîïÓÔ;HNO3ðyP,žHNO39¢`W0ñòóÅ,CCl4<ôðXv,çÁ<ðXv,õö÷,øù#úòûóÅ,BAîïÓÔ;çÁyüz,ýNa[Al(OH)4]?@MNeþÿAl(OH)3,!H2CO3æAl(OH)3UÁ#$,CAîïÓÔ;BaSO3çÁ?@MNBaSO4,a%¶éBa(NO3)2,DAîïÓÔ。6.【34】D【56】&'lU()¹*U§¨+Ì#N,-,õöI./,AAîïÓÔ;/¨ÀÁ0æÁtËzM1÷23U5?@MNt#0æõ#,45½:K
9,õöI./,BAîïÓÔ;!·`,]³9zM?@,MNø#]æt9,678Wr9ì]U:3;<=>Q,õöI./,CA2+îïÓÔ;?@AlCuBCDE,Cu(OH)2OPFa.,DAîïÓÔ。7.【34】C【56】ÒÓÔ,G#HIðiJð(að),ר#?@w#,AABC;=I`,è5vKSðLM,BAB--2-C;aðzM#?@,Ið?@hiHCOOH+4OH-2eCO3+3H2O,CAST;bðIð?@hiO2+--2H2O+4e4OH,NOPQ+,2.24LO2UKLURi0.1mol,0.1molO2S?@`TIUÌM0.4molIv,I0.2molV9.2gjÁW#,DABC。$% 1&('5&)书8.【34】A【56】16gO2æO3Xï9¢lI1molO,AAST;14gYZUKLURi0.5mol,1[YZXv1[π--,\0.5molYZ0.5molπ,BABC;CH3COOýzM5,lCH3COO]É^P0.1NA,CABC;NOPQ+,2.24LH2UKLURi0.1mol,?@MN0.1molH2,ÌM0.2molIv,DABC。9.【34】D【56】_!·¸,H2S`aÌ#Ñbc,deS?@<Å>?@,AAST;a²`,H2SU`aÌ#Ñi50%,f`a`,H2S、S2、H2UKLURX]Xgi40%、20%、40%,BAST;bcG#HhiÏ!?@jÑ,klmã`a6¨`,CAST;?@K¤I1n9¢,K9¢Xv]bc,·¸R,¹opqr+,K`a¢st?@K,àuPv,H2S`aÌ#Ñw^,DABC。10.【34】C【56】xjly½z,jlK{<À;x|ly½z,jlK{<õ#À,¬#}u?@uQ,^[#ï~I_!,Iר,zM?@½<2SCl2+2H2O4HCl+SO2↑+S↓,9¢Xv]bc,S?-@<b?@,SCl2<#H<}uH,A、BAST;ù#tyüz,NO3¹Áqr+ÊSO2#N2-SO4,CABC;|lWSO2,>ý
ude,DAST。11.【34】B【56】e9¢<Cl2,faiCl2,ciClO2,ClO2:I##,½§¨DEH,AAST;N2<
9VWNNX{,aiN2,ciNO2,xNO2?@MNHNO3æNO,?@<#ï?@,BABC;À¹2--
9l:;`ÎÆe,faiS,ciSO2,diNa2SO3、NaHSO3à,SO2、SO3æHSO3:I}u,ÁKMnO4?@pºe,CAST;çÁË<{nòHæeH,½¨P{¶、àUM,DAST。12.【34】A【56】PEPUXvÙ ½z,XuvN1[,YN2[,WN5[,ZuvN4[,Zuv TúI4[Iv。¡Wuv¢TIv£¤i!!,f2+a=3a,5âa=1,Wi¥,îïÓÔ;¡WuvIv£¤i!!,f2+8+a=3a,5âa=5,Wi¦,îïÓÔ。67,§x¨z©ª½«z,Xit,Yi,Zi。O、C、HUIJÒ¬w^,AAST;uv®:P>C>O,BABC;¯·¯v+,H2O2NXvt,¯·+i¢,±²cPC2H6,CABC;PH3UXv <°,<ðXv,xCH4<ôðXv,\Xvð:PH3>CH4,DABC。13.【34】D【56】j±²o、2n³´,AAST;Yi¦ÁY,¹ÁµLl5MN¦ÁæY°,BAST;jXvluv¶·Uuvi¸uv,¹XvlP¶·Uuvi¸uv,CAST;jNH師2師º5MN帨師、CH3CH2CH(OH)COOHæHBr,CH3CH2CH(OH)COOHæHBr»NaOH?@,1molj AD¼2molNaOH(80gNaOH),DABC。14.【34】C-7.50.5-8-8【56】¬a²½N¾ÚKa(HClO)=10=10×10,]R-i10,AABC;¬uv¿o,ùlÀ¹$% 2&('5&)---3.4-7.54nùÁv:n(HClO)+n(ClO)+2n(Cl2)+n(Cl)=0.2mol,BABC;K2=K1·Ka(HClO)=10×10=10-10.9,CAST;ÒÓÔ,pH=3.0~6.0`,c(HClO)äc,#©ä#,DABC。-15.【34】(1)NH3、Cl(2X,1[1X)(2)①A(2X)wÂ②2CoCl+10NH+2NHCl+HO2[Co(NH)]Cl+2HOÃ2CoCl+10NH·HO+2NHCl+23422△36322324wÂHO2[Co(NH)]Cl+12HO(2X,KLBCÄÅÆ`âX,ÇÈqrÉ1X,¡?@Kl22△3632CoCl2ÈNCoCl2·6H2O,MNKlH2OUs]1@ÊRÉX)(3){ËRÆïKƶ1.0×10-3mol·L-1,2̺25℃+UIÍÑ(1X),¡IÍѹ-1120~134μS·cm,fÆïKNi[Co(NH3)4Cl2]Cl,ºÎ7ÏЫ(1X)3+3+(4)①Co(OH)3ÑP,Co(OH)3PUÒXlCo¸Ø,pâCo©$PI2(2X)3+3++②d.ÓËRÔÁ(2X)[Co(NH3)6]幑幐Co+6NH3(1X),NH3æH?@23`aSKMÕMN3+3+-Co,Co¸bc,#IMNI2(1X)2+-【56】(1)[Co(NH3)5Cl]Cl2UÆ5v<[Co(NH)5Cl],Æ¢INH3æCl,Æs]i6。(2)①333Ki60℃,@p¨Ö>;②w§G#H,Ö>,×§#H,}uKi,Ø?@wÂi2CoCl+10NH+2NHCl+HO2[Co(NH)]Cl+2HOÃ2CoCl+10NH·HO+2NHCl+23422△36322324wÂHO2[Co(NH)]Cl+12HO。22△3632(3)ÒÓÔ,ƶr@¸U,§2̺25℃+UIÍÑ,¬]!ÆïKN。3+3+(4)①ÙäÚÇa、by,ÙïCo(OH)3U¸i½z:Co(OH)3PUÒXlCo¸Ø,pâCo#3+3+©$PI2;②ÛÜïÝ5vÀ¹`a:[Co(NH3)6]幑幐Co+6NH3,tÔÁ,c(NH3)w^,23`aSKMÕ,Ý5v¸bc,º#,ÞÚÇdlßà:ÓËRÔÁ。16.【34】(1)Cu(1X)Fe(1X)(2)bcá¢9¢·âh,Ï!?@jÑ(3Ï!uÐ/¨ÑãäåX,2X) H2SO4(1X)(3)Fe2O3、CuO(2X,1[1X) æ¾çèhUSn^[,Ï!Ñ(2X)2--(4)SnO3+2CO2+3H2OSn(OH)4↓+2HCO3(2X,KLBCÄÅÆ`âX)3119×8槡×(5)0.6489(2X) -73(2X)4NA×(0.6489×10)【56】(1)¹^[éêl,ÂsPdsë;S、Fe、Cu、Snl,oìuvÅNrIv] AU^[iFe。(2)íîá§bcá¢9¢·âh,Ï!?@jÑ;ï9UVWNX<SO2,ðñ#、G##、98.3%ÀÁžâãÀÁ。(3)Fe2O3、CuOPÁË;çèhòóIôKL,ÞßõÊÞßïöÍFçl½7æ¾Sn^[,Ï!Ñ。(4)ôÁËžÜRUCO2MNSn(OH)4æNaHCO3。槡3(5)÷ôøù¡úÐûPüýþ¡ú,1[¡ú8[Sn。2[ôU ÿ!5i×0.6489nm。1nm=4119×8-7=-310cm,÷ô¸ρ-73g·cm。(0.6489×10)NA$% 3&('5&)!17.【34】(1)(1X)ΔH3=ΔH1+ΔH2(1X,ºÎST$åX)(2)CO(1X)B(2X)-1(3)CO(g)+2H2(g)CH3OH(g) ΔH=-96.5kJ·mol(2X,ÅÈPìÉ1X,ΔHBCâX)(4)9(2X)(5)BD(2X,%r1[â1X,A%ÃB%âX)0.50.1×84××8410×24.24.2(6)0.5(1X) Ã(2X)22×4231.12.1×84×(×84)34.24.2【56】(1)¬&'Ì(,?@①+?@②=?@③。(2)“#)”zM?@:CH4(g)+Fe3O4(s)3FeO(s)+CO(g)+2H2(g),CO、H2UKLURÙi12,*+2,Ú,¹500~650℃-,H2、COUKLURÙcP21,deCOzM.?@ÙH2/py。(3)¬+30·ÈÚ>#$ù1h,21+,1[COXvæ2[H2XvMN1[CH3OHXv3=Ú1eVUR。c(OH-)·c(NH+)-4-5c(OH)×0.18--5-1(4)Kb==1.8×10≈,c(OH)≈1.0×10mol·L,pH=14-pOH≈14-5=9。c(NH3·H2O)0.1(5)G#H·âh¤45?@jÑ,45`aMÕ,Ï!`aÌ#Ñ,AABC;1ã·¸+,bcv#,`aSKMÕ,\p1>p2,BAST;v#1ã`,_!·¸,CO`aÌ#Ñw^,de`aíKMÕ,S?@<=>?@,`a¯]¤·¸I.,S?@<=>?@,_·,`a¯]w^,\K(a)>K(b)=K(c),CABC;·¸1ã,bcv#,í?@jÑbc,Ví?@jÑ:v(b)>v(c);1ãv#,_!·¸,í?@jÑbc,Ví?@jÑ:v(c)>v(a),DAST。(6)¬O^[¿o½zn(H2O)=(2-1.1-0.4)mol=0.5mol,â